Inverses of Matrices Problem 1.6 (complexity 2). Solution
Given: two matrices:
and
.
Solve the equation
XA=B.
Solution
Multiplying the both side of the equation X·A = B by
A-1, we have
X·A·A-1 =
B·A-1.
Since A·A-1 = I2, then
X = B·A-1
If A is a square matrix of order 2
,
then its inverse matrix is