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Inverses of Matrices
   Problem 1.6 (complexity 2). Solution

Given: two matrices:
    and   .
Solve the equation XA=B.

Solution
Multiplying the both side of the equation X·A = B by A-1, we have X·A·A-1 = B·A-1. Since A·A-1 = I2, then X = B·A-1
If A is a square matrix of order 2 , then its inverse matrix is
 
 
 
 Answer:   .


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