Inverses of Matrices Problem 1.5 (complexity 2). Solution
Given: two matrices:
and
.
Solve the equation
AX=B.
Solution
Multiplying the both side of the equation
A·X = B
by
A-1,
we have
A-1·A·X =
A-1·B.
Since A-1·A = I2, then
X = A-1·B
If A is a square matrix of order 2
,
then its inverse matrix is