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Inverses of Matrices
   Problem 1.5 (complexity 2). Solution

Given: two matrices:
    and   .
Solve the equation AX=B.

Solution
Multiplying the both side of the equation A·X = B by A-1, we have A-1·A·X = A-1·B. Since A-1·A = I2, then X = A-1·B
If A is a square matrix of order 2 , then its inverse matrix is
 
 
 
 Answer:   .


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